En un triángulo ABC, se traza la bisectriz interior BD. Donde AB=6, BC=9 y AC=10. Determinar AD
alternativas:
1
2
3
4
alternativas:
1
2
3
4
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Respuesta:
4
Explicación paso a paso:
AB/BC = AD/DC
6/9 = AD/DC
2/3 = AD/DC
AD = 2K
DC = 3K
AD + DC = 10
2K + 3K = 10
5K = 10
K = 2
AD = 2K
AD = 2(2)
AD = 4