Respuesta:
[tex]50\pi cm^{2}[/tex] ; La correcta es la Opción b )
Explicación paso a paso:
Longitud del arco: [tex]L = 5\pi[/tex]
Ángulo: [tex]\alpha = 45[/tex]
[tex]Area: A = ?[/tex]
Fórmula:
[tex]A = \frac{L^{2} }{2\alpha }[/tex]
[tex]Convertimos (45grados) en (radian): 45grados = \frac{\pi }{4}[/tex]
[tex]A = \frac{(5\pi cm)^{2} }{2(45)} =\frac{25\pi ^{2}cm^{2} }{2(\frac{\pi }{4}) } =\frac{25\pi ^{2}cm^{2} }{\frac{\pi }{2} } = \frac{2(25\pi ^{2} )}{(\pi )}cm^{2}[/tex]
[tex]A = 50\pi cm^{2}[/tex]
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Respuesta:
[tex]50\pi cm^{2}[/tex] ; La correcta es la Opción b )
Explicación paso a paso:
Longitud del arco: [tex]L = 5\pi[/tex]
Ángulo: [tex]\alpha = 45[/tex]
[tex]Area: A = ?[/tex]
Fórmula:
[tex]A = \frac{L^{2} }{2\alpha }[/tex]
[tex]Convertimos (45grados) en (radian): 45grados = \frac{\pi }{4}[/tex]
[tex]A = \frac{(5\pi cm)^{2} }{2(45)} =\frac{25\pi ^{2}cm^{2} }{2(\frac{\pi }{4}) } =\frac{25\pi ^{2}cm^{2} }{\frac{\pi }{2} } = \frac{2(25\pi ^{2} )}{(\pi )}cm^{2}[/tex]
[tex]A = 50\pi cm^{2}[/tex]