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P1 = 1 atm
V1 = 16,4 L
T1 = 273 + 47º C = 320º K
P2 = 0,8 atm
V2 = 22 L
T2 = ?
Formula
p1.v1/t1 = p2.v2/t2
Despejando : T2
t2 = t1.p2.v2 / p1.v1
t2 = 320 °K * 0.8 atm* 22L / 1 atm* 16.4 L
T2 = 343.41 °K