en la tabla se muestran los pesos de algunos alimentos que están en la cocina de una sala allá los pesos que se indican a continuación arroz , frejol , papa ayudemme
[tex]\bold{Frijol = \dfrac{1 }{6 } \ kg }\\\\\\ \bold{Papa= \dfrac{3 }{5 } \ kg } \\\\\\ \bold{Arroz= \dfrac{5 }{8 } \ kg }[/tex]
Nos pide el peso de
[tex]\bold{Arroz, Frijol y Papa}\\\\\bold{Arroz + Frijol + Papa=Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg+ \dfrac{3}{5}\ kg + \dfrac{5}{8}\ kg=Peso \ total } \\\\\\\bold{\dfrac{1*20}{6*20}\ kg+ \dfrac{3*24}{5*24}\ kg + \dfrac{5*15}{8*15}\ kg=Peso \ total }\\\\\\\bold{\dfrac{20}{120}\ kg+ \dfrac{72}{120}\ kg + \dfrac{75}{120}\ kg=Peso \ total }\\\\\\\bold{\dfrac{167}{120}\ kg=Peso \ total }[/tex]
[tex]\bold{Arroz\ y\ Frijol }\\\\\bold{Arroz + Frijol =Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg+ \dfrac{3}{5}\ kg =Peso \ total } \\\\\\\bold{\dfrac{1*5}{6*5}\ kg+ \dfrac{3*6}{5*6}\ kg=Peso \ total }\\\\\\\bold{\dfrac{5}{30}\ kg+ \dfrac{18}{30}\ kg =Peso \ total }\\\\\\\bold{\dfrac{23}{30}\ kg=Peso \ total }[/tex]
[tex]\bold{Arroz\ y \ Papa}\\\\\bold{Arroz+ Papa=Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg + \dfrac{5}{8}\ kg=Peso \ total } \\\\\\\bold{\dfrac{1*8}{6*8}\ kg + \dfrac{5*6}{8*6}\ kg=Peso \ total }\\\\\\\bold{\dfrac{8}{48}\ kg+ \dfrac{30}{48}\ kg=Peso \ total }\\\\\\\bold{\dfrac{38}{48}\ kg=Peso \ total } \\\\\\\bold{\dfrac{19}{24}\ kg=Peso \ total }[/tex]
Verified answer
Suma de Fracciones:
Siempre debemos tener el mismo denominador para sumar el numerador
[tex]Fraccion = \bold{\dfrac{Numerador }{Denominador } }[/tex]
Datos
[tex]\bold{Frijol = \dfrac{1 }{6 } \ kg }\\\\\\ \bold{Papa= \dfrac{3 }{5 } \ kg } \\\\\\ \bold{Arroz= \dfrac{5 }{8 } \ kg }[/tex]
Nos pide el peso de
[tex]\bold{Arroz, Frijol y Papa}\\\\\bold{Arroz + Frijol + Papa=Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg+ \dfrac{3}{5}\ kg + \dfrac{5}{8}\ kg=Peso \ total } \\\\\\\bold{\dfrac{1*20}{6*20}\ kg+ \dfrac{3*24}{5*24}\ kg + \dfrac{5*15}{8*15}\ kg=Peso \ total }\\\\\\\bold{\dfrac{20}{120}\ kg+ \dfrac{72}{120}\ kg + \dfrac{75}{120}\ kg=Peso \ total }\\\\\\\bold{\dfrac{167}{120}\ kg=Peso \ total }[/tex]
[tex]\bold{Arroz\ y\ Frijol }\\\\\bold{Arroz + Frijol =Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg+ \dfrac{3}{5}\ kg =Peso \ total } \\\\\\\bold{\dfrac{1*5}{6*5}\ kg+ \dfrac{3*6}{5*6}\ kg=Peso \ total }\\\\\\\bold{\dfrac{5}{30}\ kg+ \dfrac{18}{30}\ kg =Peso \ total }\\\\\\\bold{\dfrac{23}{30}\ kg=Peso \ total }[/tex]
[tex]\bold{Arroz\ y \ Papa}\\\\\bold{Arroz+ Papa=Peso \ total }\\\\\bold{\dfrac{1}{6}\ kg + \dfrac{5}{8}\ kg=Peso \ total } \\\\\\\bold{\dfrac{1*8}{6*8}\ kg + \dfrac{5*6}{8*6}\ kg=Peso \ total }\\\\\\\bold{\dfrac{8}{48}\ kg+ \dfrac{30}{48}\ kg=Peso \ total }\\\\\\\bold{\dfrac{38}{48}\ kg=Peso \ total } \\\\\\\bold{\dfrac{19}{24}\ kg=Peso \ total }[/tex]
Espero que te sirva, salu2!!!!