En la formula A = 2C (b+a), al despejar b la formula que obtengo es:
A. (2AVC) + a = b
B. (AV2C)- a = b
C. (a.AVC)- a = b
D. (2CVA) - a = b
A. (2AVC) + a = b
B. (AV2C)- a = b
C. (a.AVC)- a = b
D. (2CVA) - a = b
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Explicación paso a paso:
A = 2C (b+a)
A/2C = b+a
(A/2C) - a = b