Question

En 523g de N2O3:
a) ¿Cuantos moles hay?
b)¿Cuantas moleculas hay?
c)¿Cuantos litros en c.n.(condiciones normales) hay?

Answer 1

Mm N2O3 = 76 g/mol

a) ¿Cuantos moles hay?

mol = masa/Mm
mol = 523 g / 76 g/mol
mol = 6.882

b)¿Cuantas moleculas hay?

       1 mol ----- 6.022 x 10 ²³ moléculas
6.882 mol -----          x

           x = 4.144 x 10²⁴ moléculas

c)¿Cuantos litros en c.n.(condiciones normales) hay?
 
1 mol en CN T = 25 ºC y  1 atm

P V = n  x R x T

n (moles)= 6.882

R = 0.0821 (atm L / mol K)

T = 25 + 273 = 298 K

V = n x R x T / P

V = 6.882 mol x  0.0821 (atm L / mol K) x 298 K
     ````````````````````````````````````````````````````````````
                                 1 atm

V = 168.37 L