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x+y+2z=0
x-y+z=4
_________ -
2y+z=-4
2.) Eliminasi kedua:
3x+2y+z=2 } ×1
x+y+2z=0 } ×3
_________ -
=>
3x+2y+z=2
3x+3y+6z=0
_________ -
-y-5z=2 } ×-1
3.) Eliminasi ketiga
2y+z=-4 } ×1
y+5z=-2 } ×2
_________ -
=>
2y+z=-4
2y+10z=-4
_________ -
-9z=0
z=0/-9
z=0
2y+z=-4
2y+0=-4
y=-2
x-y+z=4
x-(-2)+0=4
x+2=4
x=2
Jadi nilai x, y, dan z berturut-turut adalah {2, -2, 0}