x(x+1)=156
x=12
x^2+x=156
x^2+x-156=0
x -12
x 13
(x-12)(x+13)=0
x=12 o x=-13 como x no puede ser negativo
x+1=13
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x(x+1)=156
x=12
x(x+1)=156
x^2+x=156
x^2+x-156=0
x -12
x 13
(x-12)(x+13)=0
x=12 o x=-13 como x no puede ser negativo
x=12
x+1=13