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x²y(m+n-4) + xy(m-1-n) ≡ 0
Por lo tanto:
m+n-4 = 0 m-1-n = 0
m + n = 4 m - n = 1
Observamos, por sistema de ecuaciones que:
2m = 5
m = 5/2
n = 3/2
Piden: 4mn
4(5/2)(3/2)
Simplificando obtenemos: 15
Es la respuesta.