[6.5 ]= busca el número inmediato superior
7 - 6.5 = 0.5
buscar el antilogaritmo de la diferencia: (inv. del log)
antilog 0.5 = 3.16
[ H⁺] = 3.16 X 10⁻⁷
[7.5 ] = 8 - 7.5 =0.5
[OH⁻ ] = 3.16 X 10⁻⁸
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pH = 14 - pOH
pH = 14 - 7.5
pH = 6.5
[6.5 ]= busca el número inmediato superior
7 - 6.5 = 0.5
buscar el antilogaritmo de la diferencia: (inv. del log)
antilog 0.5 = 3.16
[ H⁺] = 3.16 X 10⁻⁷
[7.5 ] = 8 - 7.5 =0.5
antilog 0.5 = 3.16
[OH⁻ ] = 3.16 X 10⁻⁸