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triciclos = 3 ruedas bicicletas = 2 ruedas
x + y = 20 despejando x=20-y
3x + 2y = 54 sustituyendo
3(20-y) + 2y = 54
60 - 3y + 2y = 54
60 - 54 = 3y - 2y
6 = y
reemplazando
x + 6 = 20
x = 20-6
x = 14
respuesta 6 bicicletas y 14 triciclos