Respuesta:
[tex]2\alpha =3C_{\alpha}\\2\alpha =3(90-\alpha)\\2\alpha =3(90)-3\alpha\\5\alpha=3(90)\\ \alpha=54°[/tex]
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[tex]2x = 3(90 - x) \\ 2x = 270 - 3x \\ 2x + 3x = 270 \\ 5x = 270 \\ x = \frac{270}{5} \\ x = 54[/tex]
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Respuesta:
[tex]2\alpha =3C_{\alpha}\\2\alpha =3(90-\alpha)\\2\alpha =3(90)-3\alpha\\5\alpha=3(90)\\ \alpha=54°[/tex]
✔Planteamiento del problema:
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✔Resolvemos :
[tex]2x = 3(90 - x) \\ 2x = 270 - 3x \\ 2x + 3x = 270 \\ 5x = 270 \\ x = \frac{270}{5} \\ x = 54[/tex]