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di = 20cm ----> ri = 10cm
Ai = πdi²/4
Af = Ai - 64π
df = ?
entonces, reemplazamos valores, sería:
Af = π(20)² /4 - 64π
πdf²/4 = 100π - 64π , simplificando los π
df²/4 = 36
df² = 144 ----> df = √144 = 12cm , rf = 6cm
entonces de lo anterior, el radio debe disminuirse en:
R = 10 - 6
R = 4cm
esta es la respuesta