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x²=3x
x²-3x=0
x(x-3)=0
x=0 x-3=0
x=0 x=3
la respuesta es 3
3²=3(3)
9=9
k² = 3k
k² - 3k = 0 (factorizamos sacamos factor comun k)
k( k - 3) =0 Tiene 2 soluciones
k = 0
o
k -3 = 0
k = 3
Soluciones (0 , 3)