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h=60J/5kg*m/s
h=12m
Pozdro
60 J = mgh g=9,81 m=0,5 kg
h=60/(0,5*9,81) = 12,23 m
dane m=0,5kg, Eko=60J, g=10m/s2=10N/kg,
szukane hmax
Eko = Epmax = mghmax
hmax = Eko/mg = 60J/0,5kg*10m/s2 = 12m
Ciało doleci na max. wysokość 12m.
...................pozdrawiam