1.
[tex] \frac{ { \frac{1}{4} }^{2} \times ( \frac{2}{3}) \times 3 }{6 \times \sqrt[3]{30 + \frac{1}{3} } } = \frac{( \frac{1}{16}) \times 2 }{6 \times \sqrt[3]{ \frac{91}{3} } } = \frac{ \frac{1}{8} }{6 \times 3.12}[/tex]
[tex] \frac{1}{149.76} = 0.006[/tex]
2.
[tex] \frac{4 \times 3 - ( {\frac{1}{3})}^{2} }{2} - \frac{3(2)( \frac{1}{3}) + \frac{1}{4}}{ \frac{2}{3} } + \frac{1}{4} [/tex]
[tex]\frac{ \frac{107}{9} }{2} - \frac{ \frac{9}{4} }{ \frac{2}{3}} + \frac{1}{4} = \frac{107}{18} - \frac{27}{8} + \frac{1}{4} [/tex]
[tex] \frac{428 - 243 + 18}{72} = \frac{203}{72} = 185.25 [/tex]
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Verified answer
1.
[tex] \frac{ { \frac{1}{4} }^{2} \times ( \frac{2}{3}) \times 3 }{6 \times \sqrt[3]{30 + \frac{1}{3} } } = \frac{( \frac{1}{16}) \times 2 }{6 \times \sqrt[3]{ \frac{91}{3} } } = \frac{ \frac{1}{8} }{6 \times 3.12}[/tex]
[tex] \frac{1}{149.76} = 0.006[/tex]
2.
[tex] \frac{4 \times 3 - ( {\frac{1}{3})}^{2} }{2} - \frac{3(2)( \frac{1}{3}) + \frac{1}{4}}{ \frac{2}{3} } + \frac{1}{4} [/tex]
[tex]\frac{ \frac{107}{9} }{2} - \frac{ \frac{9}{4} }{ \frac{2}{3}} + \frac{1}{4} = \frac{107}{18} - \frac{27}{8} + \frac{1}{4} [/tex]
[tex] \frac{428 - 243 + 18}{72} = \frac{203}{72} = 185.25 [/tex]