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hallando n = numero de moles
Ca3 ( P03 )2 --> 1 mol Ca3 ( P03 )2 es equvalente a 278,18 g
X mol Ca3 ( P03 )2 sera equivalente a 20 g
X= 20 g / 278,18 g --> 0.0719 moles de Ca3 ( P03 )2
Volumen (v) = 1200 ml --> 1.2 l
reemplazamos
M= 0.0719 / 1.2
M= 0.06 mol . dm³ (aprox)