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B)2(x+1) =3x+5
C)x+10=2x+5
D) x+7=(35+7):2=21
A) 2x+2=20:10 -----------> 2x+2=2 (20 dividido 10 es 2), entonces despeja x, >> x = 0
B) 2(x+1) =3x+5 ---------> (aplica distributiva) 2x + 2 = 3x + 5, pasa las x de un solo lado, >> x = -3
C) x+10=2x+5 ------------> pasa las x de un solo lado >> x = 5
D) x+7=(35+7):2=21 ---> x + 7 = 21 = 21 despeja x, entonces >> x = 14