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( x- 3)³ Aplicamos productos notables (a - b)³ = a³ -3a²b +3ab² -b³
( x - 3)³ = x³ -3(x²)(3) +3(x)(3²) -3³ =
x³ - 9x² + 3x(9) -27 =
x³ - 9x² +27x -27
( x + 2)² Aplicamos productos notables ( a + b)² = a² +2ab + b²
(x +2)² = x² + 2(x)(2) +2² =
x² +4x +4
(2x +1)³ = (2x)³ +3(2x)²(1) +3(2x)(1²) +1³ =
8x³ +3(4x²) +6x +1 =
8x³ +12x² +6x +1