Respuesta:
[tex] \sqrt{3x + 9} = 6 \\ 3x + 9 = {6}^{2} \\ 3x = 36 - 9 \\ x = \frac{27}{3} = 9 \\ x = 9[/tex]
[tex] \sqrt{6x + 9} = x - 3 \\ 6x + 9 = {(x - 3)}^{2} \\ 6x + 9 = {x}^{2} - 6x + 9 \\ 6x = {x}^{2} - 6x \\ 12x = {x}^{2} \\ 12x - {x}^{2} = 0 \\ \frac{ - ( - 12) \: ± \: \sqrt{ {( - 12)}^{2} - 4 \times 1 \times 0} }{2 \times 1} = x \\ \frac{ 12\: ± \: \sqrt{ 144 - 4 \times 1 \times 0} }{2 \times 1} = x \\ \frac{ 12\: ± \: 12}{2} = x \\ \frac{12 + 12}{2} = x \\ 12 = x \\ \frac{12 - 12}{2} = x \\ 0 = x[/tex]
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Respuesta:
[tex] \sqrt{3x + 9} = 6 \\ 3x + 9 = {6}^{2} \\ 3x = 36 - 9 \\ x = \frac{27}{3} = 9 \\ x = 9[/tex]
[tex] \sqrt{6x + 9} = x - 3 \\ 6x + 9 = {(x - 3)}^{2} \\ 6x + 9 = {x}^{2} - 6x + 9 \\ 6x = {x}^{2} - 6x \\ 12x = {x}^{2} \\ 12x - {x}^{2} = 0 \\ \frac{ - ( - 12) \: ± \: \sqrt{ {( - 12)}^{2} - 4 \times 1 \times 0} }{2 \times 1} = x \\ \frac{ 12\: ± \: \sqrt{ 144 - 4 \times 1 \times 0} }{2 \times 1} = x \\ \frac{ 12\: ± \: 12}{2} = x \\ \frac{12 + 12}{2} = x \\ 12 = x \\ \frac{12 - 12}{2} = x \\ 0 = x[/tex]