[tex]12x^2+11=0[/tex]
Restamos el 11 de ambos lados
[tex]12x^2+11-11=0-11[/tex]
Simplificamos
[tex]12x^2=-11[/tex]
Dividimos ambos lados entre 12
[tex]\frac{12x^2}{12}=\frac{-11}{12}[/tex]
[tex]x^2=-\frac{11}{12}[/tex]
[tex]x=\sqrt{-\frac{11}{12}},\:x=-\sqrt{-\frac{11}{12}}[/tex]
[tex]\sqrt{-\frac{11}{12}}:i\frac{\sqrt{33}}{6}[/tex]
[tex]-\sqrt{-\frac{11}{12}}:-i\frac{\sqrt{33}}{6}[/tex]
[tex]x=i\frac{\sqrt{33}}{6},\:x=-i\frac{\sqrt{33}}{6}[/tex]
[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]
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Verified answer
RESOLVER:
[tex]12x^2+11=0[/tex]
Restamos el 11 de ambos lados
[tex]12x^2+11-11=0-11[/tex]
Simplificamos
[tex]12x^2=-11[/tex]
Dividimos ambos lados entre 12
[tex]\frac{12x^2}{12}=\frac{-11}{12}[/tex]
Simplificamos
[tex]x^2=-\frac{11}{12}[/tex]
[tex]x=\sqrt{-\frac{11}{12}},\:x=-\sqrt{-\frac{11}{12}}[/tex]
[tex]\sqrt{-\frac{11}{12}}:i\frac{\sqrt{33}}{6}[/tex]
[tex]-\sqrt{-\frac{11}{12}}:-i\frac{\sqrt{33}}{6}[/tex]
[tex]x=i\frac{\sqrt{33}}{6},\:x=-i\frac{\sqrt{33}}{6}[/tex]
[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]