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3a+b=11 6-b=4
6-4=b
eliminamos "b" 2=b
5a =15
a=3 por lo tanto :
remplazamos "a" a=3 y b=2
1) 2a - b = 4
2) 3a + b = 11
Resolvemos:
2a - b = 4
3a + b = 11
-------------------
5a + 0b = 15
5a = 15
a = 15/5
a = 3
El valor de a lo reemplazamos en la segunda ecuación
3a + b = 11
3 (3) + b = 11
9 + b = 11
b = 11 - 9
b = 2
Respuesta.
a = 3
b = 2