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(1+x²) dy/dx = xy
(1/y) dy = x/(1+x²) dx, misal u = 1+x²
du = 2x dx
∫(1/y) dy = ∫x/(1+x²) dx
∫(1/y) dy = ∫(1/2u) du
ln y + C = (1/2).ln u + C
ln y + C = (1/2).ln (1+x²) + C
2. x² dy/dx + y² = 0
x² dy/dx = -y²
∫(-1/y²) dy = ∫(1/x²) dx
(1/y) + C = (-1/x) + C
3. dy/dx = (1 + x).(1+y)
∫(1/(1+y) dy = ∫(1+x) dx
ln (1+y) + C = x + (1/2)x² + C