Odpowiedź:
ms=5%×400g/100%
ms=20g
M Na2CO3=2×23+12+3×16=106g/mol
M Na2CO3×2H2O=2×23+12+3×16+4×1+2×16=142g/mol
106g/mol-------20g
142g/mol-------x
x=142g/mol×20g/106g/mol
x=26,79g soli uwolnionej
mrozp=mr-ms
mrozp=400g-26,79g
mrozp=373,21g
d rozp = 1g/cm³
vrozp=373,21 cm³
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Odpowiedź:
ms=5%×400g/100%
ms=20g
M Na2CO3=2×23+12+3×16=106g/mol
M Na2CO3×2H2O=2×23+12+3×16+4×1+2×16=142g/mol
106g/mol-------20g
142g/mol-------x
x=142g/mol×20g/106g/mol
x=26,79g soli uwolnionej
mrozp=mr-ms
mrozp=400g-26,79g
mrozp=373,21g
d rozp = 1g/cm³
vrozp=373,21 cm³