PGS persekutuan dalam
[tex] \sqrt{ {p}^{2} - ( {r + R)}^{2} } \\ \sqrt{ {25}^{2} - ( {8 + 12)}^{2} } \\ \sqrt{ {25}^{2} - {20}^{2} } \\ \sqrt{625 - 400} \\ \sqrt{225} \\ 15 \: cm \: (A)[/tex]
Penjelasan dengan langkah-langkah:
GSPD = √(L² - (R+r)²)
GSPD = √(25² - (8+12)²)
GSPD = √(625 - 20²)
GSPD = √(625 - 400)
GSPD = √225
GSPD = 15 cm (A)
Mapel : Matematika
Kelas : 8
Materi : Lingkaran
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PGS persekutuan dalam
[tex] \sqrt{ {p}^{2} - ( {r + R)}^{2} } \\ \sqrt{ {25}^{2} - ( {8 + 12)}^{2} } \\ \sqrt{ {25}^{2} - {20}^{2} } \\ \sqrt{625 - 400} \\ \sqrt{225} \\ 15 \: cm \: (A)[/tex]
Penjelasan dengan langkah-langkah:
GSPD = √(L² - (R+r)²)
GSPD = √(25² - (8+12)²)
GSPD = √(625 - 20²)
GSPD = √(625 - 400)
GSPD = √225
GSPD = 15 cm (A)
Mapel : Matematika
Kelas : 8
Materi : Lingkaran