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F1 = F2 = 4 N
α = 120 º
S = 1 m
W = __ ?
Dua gaya sama besar dan mengapit sudut 120º menghasikan resultan sebesar besar gaya penysunnya
R = 4 N
Usaha
W = R × S
W = (4 N) (1 m)
W = 4 J ← jawaban
catatan:
R = √(F² + F² + 2 F F cos 120º)
R = √(F² + F² - F²)
R = √(F²)
R = F = 4 N
Ok ?