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ruang sampel 2 dadu = 36
jadi n(a) = 4
n(s) = 36
maka P(a) =
=
1 , 3 , 9 , 27
n(S) = ruang sampel dadu = 36
n(A) = ruang kejadian faktor 27: (12)
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
sehingga peluang kejadiannya adalah
P(A) = n(A)/n(S) = 12/36 = 1/3