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= √(15² + 20² + 2 . 15 . 20 . cos 90)
= √(225 + 400)
= √625
= 25 N
α = 90
F1 = 15 N
F2 = 20 N
dit : R ?
dijawab :
R = √(F1²+F2² + 2xF1F2xcos α)
= √(15² + 20² + 2x15x20xcos 90)
= √(225 + 400 + 2 x 15 x 0
= √625
= 25 N