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R1 = R
F1 = F
R2 = 3R
ditanyakan :
F2 = ?
jawab :
F2/F1 = (R1/R2)²
F2/F = (R/3R)²
F2/F = 1/9
F2 = 1/9 F
jadi besar gayanya adalah 1/9 kali semula