Dua buah muatan listrik masing masing sebesar 3micro coulomb fsn 2micro coulomb. jika jarak kedua muatan adalah 10cm, gaya tolak kedua muatan adalah.....
tolong jawab yya "asal asal langsung dilaporkan"
liliput01
Diket: q1 = 3μC = 3.10^-6 C q2 = 2μC = 2.10^-6 C r = 10 cm = 10.10^-2 m = 1.10^-1m k = 9.10^9 Nm²/C² Dit: F.......? F = k.q1.q2 / r² F = 9.10^9 x 3.10^-6 x 2.10^-6 / (1.10^-1)² F = 54.10^-3/1.10^-2 F = 54.10^-1 N F = 5,4 N
q1 = 3μC = 3.10^-6 C
q2 = 2μC = 2.10^-6 C
r = 10 cm = 10.10^-2 m = 1.10^-1m
k = 9.10^9 Nm²/C²
Dit: F.......?
F = k.q1.q2 / r²
F = 9.10^9 x 3.10^-6 x 2.10^-6 / (1.10^-1)²
F = 54.10^-3/1.10^-2
F = 54.10^-1 N
F = 5,4 N