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(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
N(s) = 36
berjumlah 4 = {1, 3), (2, 2), (3, 1)
n(A) = 3
P(A) = 3/36 = 1/12
Berjumlah 5 (1,4) (2,3) (3,2) (4,1)
n(A) = 4
P(B) = 4/36 = 1/9
Peluang muncul jumlah kedua mata dadu 4 atau 7 adalah
P(A∪B) = P(A) + P(B)
= 3/36 + 4/36
= 7/36