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n(s) = 36
jawaban soal A
a = { (1,4) (4,1) (2,3) (3,2) }
n(A) = 4
peluang
p(A) = 4/36
= 1/9
jawaban soal B
a = {(2,2) (24) (2,6)
n(A) = 3 x 3
= 9
peuang
p(A) = 9/36
= 1/4
jawaban soal C
a = { (1,1) (1,2) (2,1) }
n(a) = 3
peluang
p(A) = 3/36
= 1/12
b. p (genap) 6 / 12 = 1 / 2
c. p (<4) 6 / 12 = 1 / 2