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soal A
n(a) = { (1,1) (2,6) (6,2) (3,5) (5,3) (4,4) }
= 6
Peluang = n(a)/n(s)
= 6/36
= 1/6
soal B
n(a) = {(2,6) (6,2) (3,5) (5,3) (4,4) ( 6,4) (4,6) (5,5) (6,6)}
= 9
peluang = 9 / 36
= 1/4