Drewniany klocek w kształcie sześcianu o krawędzi 10cm ma masę 0,5kg.Jakie ciśnienie wywiera na podłoże?
a = 10cm
S = a²
S = (10cm)² = 100cm² = 0,01m²
p = F/S
F = mg
p = mg/S
p = 0,5kg x 10N/kg / 0,01m² = 500Pa
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a = 10cm
S = a²
S = (10cm)² = 100cm² = 0,01m²
p = F/S
F = mg
p = mg/S
p = 0,5kg x 10N/kg / 0,01m² = 500Pa
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)