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panjang kerangka = 4(20+15+8) = 4(43) = 172 cm
panjang sisa kawat = 200 - 172 = 28 cm
= 4 ( 20 + 15 + 8 )
= 4 x 43
= 172 cm
kawat yg tersedia = 2 m = 200 cm
sisa kawat = 200 - 172 = 28 cm