Respuesta:
a)
[tex](ca-\frac{b}{c} )^2 = c^2a^2-2ab+(\frac{b}{c} )^2\\(ca-\frac{b}{c} )^2 = c^2a^2-2\frac{acb}{c}+ (\frac{b}{c} )^2\\(ca-\frac{b}{c} )^2 = c^2a^2-2ab+ (\frac{b}{c} )^2\\[/tex]
b)
[tex](a^2+b^2)^2-(a^2-b^2)^2=4a^2b^2\\(a^2+b^2)^2-(a^2-b^2)^2=a^4+2a^2b^2+b^4-a^4+2a^2b^2-b^4\\(a^2+b^2)^2-(a^2-b^2)^2=2a^2b^2+2a^2b^2=4a^2b^2[/tex]
c)
[tex](a+1)(a^2-a+1)=a^3+1\\(a+1)(a^2-a+1)=a^3-a^2+a+a^2-a+1\\(a+1)(a^2-a+1)=a^3+1[/tex]
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Respuesta:
a)
[tex](ca-\frac{b}{c} )^2 = c^2a^2-2ab+(\frac{b}{c} )^2\\(ca-\frac{b}{c} )^2 = c^2a^2-2\frac{acb}{c}+ (\frac{b}{c} )^2\\(ca-\frac{b}{c} )^2 = c^2a^2-2ab+ (\frac{b}{c} )^2\\[/tex]
b)
[tex](a^2+b^2)^2-(a^2-b^2)^2=4a^2b^2\\(a^2+b^2)^2-(a^2-b^2)^2=a^4+2a^2b^2+b^4-a^4+2a^2b^2-b^4\\(a^2+b^2)^2-(a^2-b^2)^2=2a^2b^2+2a^2b^2=4a^2b^2[/tex]
c)
[tex](a+1)(a^2-a+1)=a^3+1\\(a+1)(a^2-a+1)=a^3-a^2+a+a^2-a+1\\(a+1)(a^2-a+1)=a^3+1[/tex]