Respuesta:
1) es la B, porque
[tex] \sqrt{256 = 16} [/tex]
16 es un numero racional
2) B
[tex] {6}^{ - 2} + {3}^{ - 2} - {2}^{ 3} \\ \\ \frac{1}{36} + \frac{1}{9} - 8 \\ \\ \frac{5}{36} - \frac{288}{36} = - \frac{283}{36} [/tex]
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Respuesta:
1) es la B, porque
[tex] \sqrt{256 = 16} [/tex]
16 es un numero racional
2) B
[tex] {6}^{ - 2} + {3}^{ - 2} - {2}^{ 3} \\ \\ \frac{1}{36} + \frac{1}{9} - 8 \\ \\ \frac{5}{36} - \frac{288}{36} = - \frac{283}{36} [/tex]