1)
(x+y)² = x²+2xy+y²
(12)² = x²+y²+2(10)
144 = x²+y²+20
124 = x²+y²
2)
(4)² = x²+y²+2(3)
16 = x²+y²+6
10 = x²+y²
(x²+y²)² = x^4+y^4 + 2(3²)
(10)² = x^4+y^4 + 2(9)
100 = x^4+y^4 + 18
82 = x^4+y^4
3)
5x·(3/5) - 1 = √2·√2
3x - 1 = 2
3x = 3
x = 1
4)
(√3/3) · (√3) + (√3) · (2√3 / 3)
(3/3) + (2(3) / 3)
1 + 2
3
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Verified answer
1)
(x+y)² = x²+2xy+y²
(12)² = x²+y²+2(10)
144 = x²+y²+20
124 = x²+y²
b) 124
2)
(4)² = x²+y²+2(3)
16 = x²+y²+6
10 = x²+y²
(x²+y²)² = x^4+y^4 + 2(3²)
(10)² = x^4+y^4 + 2(9)
100 = x^4+y^4 + 18
82 = x^4+y^4
c) 82
3)
5x·(3/5) - 1 = √2·√2
3x - 1 = 2
3x = 3
x = 1
a) 1
4)
(√3/3) · (√3) + (√3) · (2√3 / 3)
(3/3) + (2(3) / 3)
1 + 2
3
c) 3