Dodawanie i odejmowanie do 25 z przekraczaniem progu dziesiątkowego.... 1. Oblicz. 19 + 3 = 17+ 5 = 23 - 4 = 25 - 7 = 18+ 4 - 5 = 24 - 5 - 6 = 22 - 5 - 1 = Daje Naj
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Odpowiedź:
19 + 3 = 19 + 1 + 2 = 20 + 2 = 22
17 + 5 = 17 + 3 + 2 = 20 + 2 = 22
23 - 4 = 23 - 3 - 1 = 20 - 1 = 19
25 - 7 = 25 - 5 - 2 = 20 - 2 = 18
18+ 4 - 5 = 18 + 2 + 2 - 5 = 20 + 2 - 5 = 20 - 5 + 2 = 15 + 2 = 17
24 - 5 - 6 = 24 - 4 - 1 - 6 = 20 - 1 - 6 = 19 - 6 = 13
22 - 5 - 1 = 22 - 2 - 3 - 1 = 20 -3 -1 = 17 - 1 = 16
Szczegółowe wyjaśnienie: