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m=10kg
Δt=20°C=20K
c=4189,9[J/(kg*K)]
Q=cmΔt=4189,9*10*20=837980J=838kJ
pozdrawiam
Hans
m=10kg
Obliczenia:
Δt=20°C=20K
c=4189,9[J/(kg*K)]
Q=cmΔt=4189,9*10*20=837980J=838kJ
Odp: Zostało dostarczone 838 kJ energii.
pozdrawiam :)