dane:
10 l wody = 10 kg
m₂ = 10 kg
t₂ = 76*C
t₁ = 15*C
tk = 36*C
szukane:
m₁ = ?
Q pobrane = Q oddane
m₁C(tk-t₁) = m₂C(t₂-tk) /:C(tk-t₁)
m₁ = m₂(t₂-tk)/(tk-t₁)
m₁ = 10kg·(76*C-15*C)/(36*C-15*C) = 19,05 kg
m₁ = ≈ 19 kg = ≈ 19 l
----------------------------
Odp. Należy dolać ok.19 litrów wody o temperaturze 15*C.
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dane:
10 l wody = 10 kg
m₂ = 10 kg
t₂ = 76*C
t₁ = 15*C
tk = 36*C
szukane:
m₁ = ?
Q pobrane = Q oddane
m₁C(tk-t₁) = m₂C(t₂-tk) /:C(tk-t₁)
m₁ = m₂(t₂-tk)/(tk-t₁)
m₁ = 10kg·(76*C-15*C)/(36*C-15*C) = 19,05 kg
m₁ = ≈ 19 kg = ≈ 19 l
----------------------------
Odp. Należy dolać ok.19 litrów wody o temperaturze 15*C.