3NaOH + H3PO4= Na3PO4+ 3H2O
( 20 g) x
Masa Na3PO4= 23*3+ 31 + 16*4= 164 g/mol
M NaOh= 23+ 16+ 1= 40 g/mol
20 g- 40
xg- 164
x= 82 g
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3NaOH + H3PO4= Na3PO4+ 3H2O
( 20 g) x
Masa Na3PO4= 23*3+ 31 + 16*4= 164 g/mol
M NaOh= 23+ 16+ 1= 40 g/mol
20 g- 40
xg- 164
x= 82 g