Do garnka wlano 2 kg wody o temperaturze 30 C . Ile ciepła trzeba dostarczyć , aby ogrzać tąwodę do temperatury 90 C?
Q= cw x m x(tk - tp)
Q= 4200 x 2 x 60
Q= 504000j
Q= 504kj
[ j/kg * k x kg x k = j]
dane;
m = 2 kg
t1 = 30*C
t2 = 90*C
Δt = 90*C-30*C = 60*C
C = 4200 J/kg*C
szukane:
Q = ?
Q = m*C*Δt
Q = 2kg*4200J/kg*C*60*C = 504 000 J
1 kJ = 1000 J
Q = 504 kJ
========
Odp. Należy dostarczyć 504 kJ ciepła.
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Q= cw x m x(tk - tp)
Q= 4200 x 2 x 60
Q= 504000j
Q= 504kj
[ j/kg * k x kg x k = j]
dane;
m = 2 kg
t1 = 30*C
t2 = 90*C
Δt = 90*C-30*C = 60*C
C = 4200 J/kg*C
szukane:
Q = ?
Q = m*C*Δt
Q = 2kg*4200J/kg*C*60*C = 504 000 J
1 kJ = 1000 J
Q = 504 kJ
========
Odp. Należy dostarczyć 504 kJ ciepła.