Question

Do 60 g roztworu soli o stężeniu 12% dodano 20 g tej soli . Oblicz stężenie procentowe otrzymanego roztworu . Wykonaj obliczenia .

Answer 1

Mr₁= 60g
Cp₁=12%
ms₁=?
Cp₁= (ms₁ * 100%) : mr₁
ms₁ * 100% = Cp₁ * mr₁
ms₁ * 100% = 12% * 60g
ms₁ * 100% = 720
ms₁ = 720:100
ms₁ = 7,2g
A skoro dodano 20 g soli to
mr₂ = mr₁ + 20g
mr₂=80g
Cp₂ = ?
ms₂ = ms₁ + 20g
ms₂ = 27,2g
cp₂ = (ms₂ * 100%) : mr₂
Cp₂ = (27,2 * 100%) : 80
Cp₂ = 2720 : 80
Cp₂ = 34%