Do 40g wody dodano 5g soli kuchennej. Oblicz stężenie procentowe otrzymanego roztworu.
Daje naj
Z góry dziękuję ;*
mw=40g
ms=5g
mr=?
Cp=?
mr=ms+mw
mr=5g+40g=45g
Cp=ms/mr*100%
Cp=5g/45g*100%
Cp≈11,1%
Cp=
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mw=40g
ms=5g
mr=?
Cp=?
mr=ms+mw
mr=5g+40g=45g
Cp=ms/mr*100%
Cp=5g/45g*100%
Cp≈11,1%
Cp=![\frac{5g}{40g+5g}=\frac{5g}{45g}=\frac{1}{9}=11,1% \frac{5g}{40g+5g}=\frac{5g}{45g}=\frac{1}{9}=11,1%](https://tex.z-dn.net/?f=%5Cfrac%7B5g%7D%7B40g%2B5g%7D%3D%5Cfrac%7B5g%7D%7B45g%7D%3D%5Cfrac%7B1%7D%7B9%7D%3D11%2C1%25)