Question

Do 30g 20% roztworu kwasu, dodano 20g wody. Oblicz stężenie procentowe końcowe.

Answer 1

mr1=30g

Cp=20%

mH2O=20g

 

 

Cp=(ms/mr1)*100%

20%=(ms/30g)*100%/*30

600%=ms*100%/100%

ms=6g

 

 

mr=mr1+mH2O

mr=30g+20g

mr=50g

 

Cp=(6g/50g)*100%

cp=600%/50

Cp=12%

 

 

Answer 2

Ja robie do tego taka tavelke  dodam ci w zalaczniuku ;P