Do 30cm3 roztworu kwasu o pH 2,3 dodano 20cm3 wody, oblicz pH danego roztworu
pH=2,3
pH=-log[H⁺]
[H⁺]=10^-pH
[H⁺]=10^-2,3
[H⁺]=5,01*10⁻³ mol/dm³
5,01*10⁻³ mol------1000cm³ roztworu
xmoli----------------30cm³ roztworu
x = 1,5*10⁻⁴ mola
DOLANO 20cm³ wody, więc
1,5*10⁻⁴ mola------50cm³ roztworu
xmoli----------------1000cm³ roztworu
x = 3*10⁻³mola kwasu
pH=-log 3*10⁻³
pH = 2,5
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pH=2,3
pH=-log[H⁺]
[H⁺]=10^-pH
[H⁺]=10^-2,3
[H⁺]=5,01*10⁻³ mol/dm³
5,01*10⁻³ mol------1000cm³ roztworu
xmoli----------------30cm³ roztworu
x = 1,5*10⁻⁴ mola
DOLANO 20cm³ wody, więc
1,5*10⁻⁴ mola------50cm³ roztworu
xmoli----------------1000cm³ roztworu
x = 3*10⁻³mola kwasu
pH=-log[H⁺]
pH=-log 3*10⁻³
pH = 2,5