Do 10l 98% roztworu kwasu zostalo domieszane 20l 25% kwasu.Ilu procentowy jest zmieszany roztwor
Cp1= 98%
mr1= 10 litrów
Cp2= 25%
mr2= 20 litrów
Cp=Cp1*mr1+Cp2*mr2/mr1+mr2
Cp=98*10+25*20/10+20=980+500/30=49,33 %
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Cp1= 98%
mr1= 10 litrów
Cp2= 25%
mr2= 20 litrów
Cp=Cp1*mr1+Cp2*mr2/mr1+mr2
Cp=98*10+25*20/10+20=980+500/30=49,33 %