Do 0,5 litra dziesięcioprocentowego roztworu kwasu octowego dolano 0,25 litra wody. Ile procent tej mieszaniny stanowi kwas octowy?
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Dane:
mr1= 500g
Cp1= 10%
m.dodanego H2O= 250g
Szukane:
mr2
ms1
Cp2
ms1= 10%* 500/100% = 50g
mr2= 500g + 250g = 750g
Cp2 = 50/750 * 100% = 5000/750 ~ 6,6%
Kwas octowy stanowi 6,6% tej mieszaniny.
mr₁=0,5l=500g
cp₁=10%
mv=0,25l=250g
ms=10%·500g/100%=50g
mr₂=500g+250g=750g
cp₂=50g/750g·100%=6,66%