ile gramów KOH znajduje sie w 500cm3 roztworu o stezeniu 2 mol/dm3
obliczenia
Vr=500cm³=0,5dm³
Cm=2mol/dm³
M(KOH)=39g/mol+16g/mol+1g/mol=56g/mol
n=?
ms=?
Cm=n/Vr /*Vr
n=Cm*Vr
n=2mol/dm³*0,5dm³
n=1mol
n=ms/M /*M
ms=n*M
ms=1mol*56g/mol
ms=56g
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Vr=500cm³=0,5dm³
Cm=2mol/dm³
M(KOH)=39g/mol+16g/mol+1g/mol=56g/mol
n=?
ms=?
Cm=n/Vr /*Vr
n=Cm*Vr
n=2mol/dm³*0,5dm³
n=1mol
n=ms/M /*M
ms=n*M
ms=1mol*56g/mol
ms=56g